Revision as of 18:12, 16 September 2008 by Cwacnik (Talk)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

I have come to the same conclusion as some others. When workign the problem you have a 1/3 chance of picking the car if you should choose first. If your friend is allowed to choose first it leaves you with a 1/2 chance considering he were to pick a goat first. The fact that there are two goats means that this mulitplication must be performed twice, thus there is a 1/3 chance again

Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal