Revision as of 13:23, 10 September 2008 by Mjwhitta (Talk)

Part a

System: $ X_{k}[n-k] \to Y_{k}[n] = (k+1)^2 \delta [n-(k+1)] $


$ X_{k}[n] \to timedelay \to sys \to Z_{k}[n]=(k+1)^2 \delta [n-N-(k+1)] $

$ X_{k}[n] \to sys \to timedelay \to Z_{k}[n]=(k+1)^2 \delta [n-N-(k+1)] $


Since $ (k+1)^2 \delta [n-N-(k+1)] $ is equal to $ (k+1)^2 \delta [n-N-(k+1)] $, the system is time-invariant.

Part b

Alumni Liaison

Have a piece of advice for Purdue students? Share it through Rhea!

Alumni Liaison