Revision as of 17:29, 9 September 2008 by Chanw (Talk)

Continuous to discrete time signal

I used the signal $ y = cos(n)\, $ as the signal of my graph

First lets look at sampling the graph at each 1 sec

Hw2.1 ECE301Fall2008mboutin.jpg

The dots are scattered everywhere, and is not periodic since $ y[n] \neq y[n+k], k \neq \R \, $

However, once we made some modifications to the graph, turn it into $ y = cos( \frac{\pi}{2} n)\, $, and sample it at every 1 sec

Hw2b ECE301Fall2008mboutin.jpg

The dotes goes periodically from 1 to -1 and back to 1, every 4 seconds.

As $ y[n] = y[n+k], k = \R \, $, the function is periodic

Creating periodic signals from no periodic signals

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Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010