Revision as of 06:36, 5 September 2008 by Serekson (Talk)

Energy of a CT signal

$ E = \int_{t1}^{t2} |x(t)|^2\ dt \! $

Power of a CT signal

$ P = \frac{1}{t2-t1} \int_{t2}^{t1} |f(t)|^2\ dt \! $

Energy of a DT signal

$ E = \sum_{n=n1}^{n2} |x[n]|^2 $

Power of a DT signal

$ P = \frac{1}{n2-n1+1} \sum_{n=n1}^{n2} |x[n]|^2 $

Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal