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AC-2 2014

P1. (a)i) $ \begin{bmatrix}x_1(t)\\x_2(t)\end{bmatrix}=\begin{bmatrix}-1 &-\frac{1}{2}\\frac{1}{2} & -1\end{bmatrix}\begin{bmatrix}x_1(t) \\ x_2(t)\end{bmatrix}+\begin{bmatrix}frac{x_0(t)}{2}\\frac{x_3(t)}{2}\end{bmatrix}=\begin{bmatrix}-1 &-\frac{1}{2}\\frac{1}{2} & -1\end{bmatrix}\begin{bmatrix}x_1(t) \\ x_2(t)\end{bmatrix}+begin{bmatrix}frac{1}{2}&0 \\ 0& frac{1}{2}\end{bmatrix}\begin{bmatrix}x_0(t) \\ x_3(t)\end{bmatrix} $

ii)

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood