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What is the norm of a complex exponential?

After class today, a student asked me the following question:

$ \left| e^{j \omega} \right| = ? $

Please help answer this question.


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Answer 1

By Euler's formular

$ e^{j \omega} = cos(j \omega) + i*sin(j \omega) $

hence,

$ \left| e^{j \omega} \right| = \left|cos(j \omega) + i*sin(j \omega) \right| = \sqrt{cos^2(j \omega) + sin^2(j \omega)} = 1 $

Answer 2

becasue: $ e^{jx} =cos(x)+ jsin(x) $

$ | e^{j \omega}|=|cos(\omega) + i*sin(\omega)|=\sqrt{cos(\omega)^2 +sin(\omega)^2}=1 $

Answer 3

Write it here


Back to ECE438 Fall 2011 Prof. Boutin

Back to ECE438

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

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