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E$ \infty $ = $ \int_{-<math>\infty $}^{$ \infty $}</math>($ \sqrt{t} $)^2 dt


E$ \infty $ = $ \int $ t dt


E$ \infty $ = ($ \frac{1}{2} $)t^2 evaluated from -$ \infty $ to +$ \infty $ = $ \infty $


P$ \infty $ = lim T$ \to $$ \infty $ $ \frac{1}{2T} $ $ \int_{-T}^{T} $

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman