Revision as of 05:15, 21 January 2009 by Lee383 (Talk | contribs)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

I don't even know how to solve the first problem.

I tried it this way.

Base step: P(0)

0*0 = 0 (0+1)! -1 =0

It is true

Inductive step: Assume P(k) is true then P(k+1) is also true.

P(k) = 1*1! + 2+2! +…………………………..+k*k! = (k+1)! -1 P(k+1) = 1*1! + 2+2! +…………………………..+(k+1)*(k+1)! = (k+2)!-1


From the first equation

(1*1! + 2+2! +…………………………..+ k*k!) +(k+1)*(k+1)! = (k+1)! -1 + (k+1)*(k+1)!.


And I am stuck at this point.

Is that correct approach?

Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal