Revision as of 17:46, 24 September 2008 by Drmorris (Talk)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

For two groups to be isomorphic, there has to be a one-to-one mapping. This is impossible for $ S_4 $ and $ D_{12} $ because $ D_{12} $ has an order of 12, and $ S_4 $ does not,$ S_4=(14)(13)(12) $, but I could be wrong. -Dan

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett