Revision as of 15:27, 7 October 2008 by Drecord (Talk)

Fourier Transform

Signal: x(t) = $ e^{3|t-1|} $

$ X(j \omega) = \int_{-\infty}^{\infty} x(t) e^{-j\omega t} dt \! $

$ = \int_{-\infty}^{\infty} e^{2|t-1|} e^{-j\omega t} dt \! $

$ = \int_{1}^{\infty} e^{2|t-1|} e^{-j\omega t} dt \! $ + $ \int_{-\infty}^{1} e^{2|t-1|} e^{-j\omega t} dt \! $

Alumni Liaison

Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin