Revision as of 17:11, 26 September 2008 by Jwise (Talk)

CT LTI signal:

$ y(t) = 3x(t-1)+x(t+3)-x(t)\! $


Part A

$ h(t) = 3\delta(t-1)+\delta(t+3)-\delta(t)\! $

$ H(j\omega) = \int_{-\infty}^{\infty}3\delta(t-1)+\delta(t+3)-\delta(t)\,dt\! $

$ H(s) = 3e^{-s} + e^{3s} - 1\! $

Part B

Signal from Question 1

$ x(t)=cos(\frac{\pi}{2}t)u(t) = \frac{1}{2}(e^{j0.5\pi}+e^{-j0.5\pi})u(t)\! $

$ y(t) = [3e^{-s} + e^{3s} - 1]\times\frac{1}{2}(e^{j0.5\pi}+e^{-j0.5\pi})u(t)\! $

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Seraj Dosenbach