DT signal & its Fourier Coefficients
$ \ x[n] = 5sin(3 \pi n + \frac{4}{\pi}) $
$ \ x[n] = \frac{5}{2j} (e^{j (3\pi n + \frac{4}{\pi})}-e^{-j (3\pi n + \frac{4}{\pi})}) $
$ \ x[n] = 5sin(3 \pi n + \frac{4}{\pi}) $
$ \ x[n] = \frac{5}{2j} (e^{j (3\pi n + \frac{4}{\pi})}-e^{-j (3\pi n + \frac{4}{\pi})}) $