Revision as of 07:57, 18 September 2008 by Cztan (Talk)

Part B: The basics of linearity

$ e^{2jt} \rightarrow linear-system \rightarrow te^{-2jt} $

$ e^{-2jt} \rightarrow linear-system \rightarrow te^{2jt} $

From these two transformations we can tell that the system is as below:

$ x(t) \rightarrow linear-system \rightarrow y(t) = tx(-t) $

Therefore, when the input, x(t) = cos(2t), the output is as follows:

$ cost(2t) \rightarrow linear-system \rightarrow y(t) = tcos(-2t) $

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett