Revision as of 12:13, 12 September 2008 by Jrathrey (Talk)

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now If X(t)-----> System---->z1(t)$ \times $a---->a.z1(t)

                                                              $ \downarrow $
      Y(t)-----> System---->z2(t)$ \times $b---->b.z2(t)

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