Revision as of 13:38, 10 September 2008 by Cocker (Talk)

I chose Kathleen Schremser's CT signal y(t)=sin(3/4*t).

In the given signal:

frequency=w=3/4

In order for a CT signal to be periodic in DT the frequency divided by 2*pi must be a rational number.

k is any integer

therefore:

$ w/(2*pi)=k/N (3/4)/(2*pi)=0.119366207318922 $

Since this is not a rational number the signal is not periodic in DT.


If we change the signal to y(t) = sin(2*pi*(3/4)*t) then;

frequency=w=3/4 * 2*pi

$ w/(2*pi)=3/4(/math> Since this is a rational number the signal is periodic in DT $

Alumni Liaison

EISL lab graduate

Mu Qiao