Practice material for Exam 1 collaboration space
You can easily talk about math here, like this:
$ e^{i\theta} = \cos \theta + i \sin \theta. $
Is this the Cauchy Integral Formula?
$ f(a)=\frac{1}{2\pi i}\int_\gamma \frac{f(z)}{z-a} \ dz $
This isn't directly related to the practice exam, but is concerning a fact discussed in class.
In one of the first lessons an important fact was provided. Namely, Suppose u is continuously a differentiable function on a connected open set $ \Omega $ and that $ \nabla u \equiv 0 $ Then u must be constant on $ \omega $.
How/Why is
$ 0 = \int\nabla u\ ds $
If we have a domain, $ \Omega $ and $ \gamma $ a curve in $ \Omega $, where $ A, B $ are end points of $ \gamma $, from vector calculus, we have
$ u(B) - u(A) = \int_\gamma \nabla u \cdot ds $.
but the integral is zero since $ \nabla u $ is zero. Hence $ u(A) = u(B) $ for any arbitrary point $ A $ and $ B $ and $ u $ is constant in $ \Omega $.
