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Simplify this summation

$ \sum_{n=-\infty}^\infty n \delta [n]  $

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Answer 1

The answer is 0 ?

Instructor's comment: Yes, it's zero. Can you justify your answer? -pm

Answer 2

The delta function is zero everywhere except when n=0 and since we are multiplying the delta by n the answer would thus be 0.

Instructor's comment: Yes, that's the idea. Now can you justify your answer "in math" instead of "in words"? -pm

Answer 3

The answer is zero since impulse function is 0 everywhere except n = 0.

Instructor's comments: Ok, I guess I am going to have to be a bit more specific. I would like to see a way to answer this question as a sequence of small changes to this expression until you get to zero. Something like
$ \begin{align} \sum_{n=-\infty}^\infty n \delta [n] &= \text{ blah } \\ &= \text{ blih} \\ &= 0 \end{align} $
Can you try that? -pm

Back to ECE438 Fall 2011 Prof. Boutin

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Questions/answers with a recent ECE grad

Ryne Rayburn