Revision as of 15:44, 8 December 2008 by Gutierjm (Talk)

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The way I went about this problem is I set Y=X-N and substituted all over the place

So if expanding on the last entry I got

E[Y] + (E[X(X-N)]-E[X]E[X-N])/(Var(x)) * (X-E[X])

             After some rearranging

E[Y] +(E[X^2]-E[XN]+E[X]^2+E[X]E[N])/(E[X^2]+E[X]^2]) * (X-E[X])

                Indep.

E[Y] + (E[X^2]-E[X]^2)/(E[X^2]-E[X]^2) * (X-E[X])

E[Y] + (X-E[X])

Thats what i got so far you sould be able to plug in values assuming this is right..theres an example like in class btw. Maybe someone could check?

Do you use law of iterated expectation here?

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva