AM Demodulation
$ r(n)= x(n)cos^2(n \theta)= \frac{1}{2} x(n) + \frac{1}{2}x(n)cos(2n\theta) $
$ Y(e^{j\theta})= R(e^{j\theta})H(e^{j\theta}) $
$ = \frac{1}{2}X(e^{j\theta})+\frac{1}{4}X(e^{j\theta-2\phi})+\frac{1}{4}X(e^{j\theta+2\phi})H(e^{j\theta}) $
$ = X(e^{j\theta}) $
