Revision as of 17:40, 15 October 2008 by Cdleon (Talk)

EXAM 1

Problem 1.

is

$ x(t) = \sum_{k = -\infty}^\infty \frac{1}{(t+2k)^{2}+1} $

periodic?

We know that for a signal to be periodic

$ x(t) = x(t + T) $

So we shift the function by a arbitrary number to try to prove the statement above

$ x(t+1) = \sum_{k = -\infty}^\infty \frac{1}{(t+1+2k)^{2}+1} $


$ x(t+4) = \sum_{k = -\infty}^\infty \frac{1}{(t+2(\frac{1}{2}+k))^{2}+1} $

Then we set $ r = \frac{1}{2}+k $ to yield,

$ = \sum_{k = -\infty}^\infty \frac{1}{(t+2r)^{2}+1} $

Since this is equivalent to x(t) the signal is periodic.

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang