Revision as of 18:07, 8 October 2008 by Ccadwall (Talk)

Inverse Fourier Transform

$ \chi(\omega) = 2 \pi \sigma (\omega - \pi) $

$ x[n] = \frac{1}{2\pi}\int_{-\infty}^{\infty} 2\pi \delta (\omega - \pi)e^{j\omega t} dw $

$ x[n] = \int_{-\infty}^\infty \delta (\omega - \pi)e^{j\omega t} dw $

$ x[n] = \int_{\pi} e^{j\omega t} dw $

$ x[n] = e^{j\pi t} $

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Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood