Revision as of 11:51, 16 September 2013 by Rhea (Talk | contribs)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Example of Computation of inverse Fourier transform (CT signals)

A practice problem on CT Fourier transform



Fourier transform

We are going to use the following:

$ X(\omega)=\frac{1}{(1+j\omega)(2+j\omega)} $


The inverse

$ X(\omega)=\frac{1}{(1+j\omega)(2+j\omega)} = \frac{1}{1+j\omega} - \frac{1}{2+j\omega} $

$ f(t)= F^{-1}\frac{1}{1+j\omega} - F^{-1}\frac{1}{2+j\omega}\, $

$ = \begin{cases} 0, & t\leq 0 \\ e^{-t}+e^{-2t}, & t\geq 0 \end{cases} $


Back to Practice Problems on CT Fourier transform

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman