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Example of Computation of Fourier transform of a CT SIGNAL

A practice problem on CT Fourier transform


Chosen Signal to Transform

The signal we will transform here will be $ x(t)=e^{2jt}*(u(t+4)-u(t-4)) $

Transform by integral

$ = \int_{-\infty}^{\infty}e^{2jt}*(u(t+4)-u(t-4))e^{-j\omega t}dt\, $

$ = \int_{-4}^{4}e^{2jt}e^{-j\omega t}dt \, $

$ = \int_{-4}^{4}e^{2jt -j\omega t}dt\, $

$ = \int_{-4}^{4}e^{t*(2j -j\omega )}dt \, $

$ = \frac{e^{2jt - j\omega t}}{2j-j\omega}]_{-4}^{4} \, $

$ = \frac{e^{8j - 4j\omega} - e^{-8j + 4j\omega}}{2j-j\omega} \, $

$ = \frac{e^{j(8 - 4\omega )} - e^{-j(8 - 4\omega )}}{j(2-\omega )} \, $

$ = \frac{2sin(8 - 4\omega )}{2-\omega }\, $


Back to Practice Problems on CT Fourier transform

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood