DT Signal:
1. Signal is periodic with N = 4
2. $ \sum_{k = 0}^{3}x[n] = (2 + j) $
3. $ == Solution == <math>a_{0} = \frac{2 + j}{4} $
DT Signal:
1. Signal is periodic with N = 4
2. $ \sum_{k = 0}^{3}x[n] = (2 + j) $
3. $ == Solution == <math>a_{0} = \frac{2 + j}{4} $