Revision as of 15:06, 26 September 2008 by Cdleon (Talk)

DT signal & its Fourier Coefficients

$ \ x[n] = 5sin(3 \pi n + \frac{4}{\pi}) $

$ \ x[n] = \frac{5}{2j} (e^{j 3\pi n - \frac{4}{\pi}}-e^{-j 3\pi n - \frac{4}{\pi}}) $

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn