1.) x(t) is real and odd.
2.) x(t) is periodic with period T = 3 and has Fourier coefficients a_k.
3.) a_k = 0 for |k| > 3.
4.) $ \frac{1}{3} \int_{0}^{3} |x(t)|^2 dt = 1 $
No idea, but it sounds good.
