Revision as of 18:03, 5 October 2008 by Jwromine (Talk)

Given that a train arrives at a train station every hour (1:20, 2:20, 3:20 etc.) and that I go to the train station from 1:00 to 2:00 how much time do I wait?

x= time I arrive y= wait time

A={x<=1:20} P[A]=1/3 B={X>=1:20} P[B]=2/3

Theorem of Total Probability fY(y)=fY/A(y)*P[A] + fY/B(y)*P[B] fY/A | 3 |_____ | | |_____|______ 1/3 fY/B | 2/3 | ______ | | | |____|______|______ 1/3 1 FY(y) | 1 |___________ | | |___________|______ 1

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