Revision as of 17:07, 23 September 2008 by Cztan (Talk)

For periodic DT signal, x[n] with fundamental period N:

$ x[n]=\displaystyle\sum_{k=0}^{n-1}a_ke^{jk\frac{2\pi}{N}n} $

The Fourier series coefficients can be calculated with:

$ a_k = \frac{1}{N}\displaystyle\sum_{n=0}^{N-1}x[n]e^{-jk\frac{2\pi}{N}n} $

Let us look for the Fourier series coefficients for the DT signal $ x[n] = cos(2\pi n) $

$ x[n] = cos(2\pi n) = \frac{e^{j2\pin}+e^{-j2\pin}}{2} $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang