Revision as of 07:42, 18 September 2008 by Cnphilli (Talk)

Homework3 Part C



How can Bob decode the message?


Bob can decode the message by breaking the message into segments of three,
and then multiplying each 3 bit segment by the inverse of the encryption vector.

Can Eve decrypt it without finding the inverse of the encryption matrix?


No, Eve would have to find the inverse of the matrix in order to decode the messages.
However, She does have enough information to determine the encryption vector. \begin{bmatrix}

    2 & 0 & 0 \\
    0 & 1 & 0 \\
    0 & 0 & 3
  \end{bmatrix}

\cdot \begin{bmatrix}

    1 & 0 & 1 \\ 
    0 & 1 & 0 \\
    4 & 0 & 1
 \end{bmatrix}

</math> -1


Matlab will tell us that the resultant matrix, the "secret" matrix, is:
$ \begin{bmatrix} -\frac{2}{3} & 0 & \frac{2}{3} \\ 0 & 1 & 0 \\ 4 & 0 & -1 \\ \end{bmatrix} $

What is the decrypted message corresponding to (2,23,3)? (Write it as a text)

(2,23,5) --> BWE

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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva