Revision as of 07:27, 18 September 2008 by Drecord (Talk)

Basics of Linearity

Definition of Linearity: For any constants a and b (that are complext numbers), and inputs x1(t) and x2(t) which yield outputs y1(t) and y2(t),

$ a * x1(t) + b * x2(t) ---> Sys ---> a * y1(t) + b * y2(t) $

We are given a linear system that behaves as follows,

$ e^{2jt} --> Sys --> t*e^{-2jt} $

and asked to find the response to find the response to cos(2t).


Solution: Using the properties of cosine we can convert cos(2t) to an exponential function.

cos(2t) = $ \frac{e^{2tj}+e^{-2tj}}{2} $

= $ \frac{1}{2}*(x1(t) + x2(t)) $

= $ \frac{1}{2}*x1(t) + \frac{1}{2}*x2(t)) $

Using the defition of linearity above,

a = $ \frac{1}{2} $

b = $ \frac{1}{2} $

x1(t) = $ e^{2tj} $

x2(t) = $ e^{-2tj} $

$ a * x1(t) + b * x2(t) ---> Sys ---> a * y1(t) + b * y2(t) $

yields the following results,

= $ \frac{1}{2}*t*x1(-t) + \frac{1}{2}*t*x2(-t)) $

plugging in for x1(-t) and x2(-t) and factoring out the t,

$ t*\frac{e^{2tj}+e^{-2tj}}{2} $

converting the exponential back to cosine yields the output of the sytem,

t*cos(2t)

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