Revision as of 16:35, 17 September 2008 by Jkubasci (Talk)

We are told that a system is linear and given inputs

$ \,x_1(t)=e^{2jt}\, $ yields $ \,y_1(t)=te^{-2jt}\, $

$ \,x_2(t)=e^{-2jt}\, $ yields $ \,y_2(t)=te^{2jt}\, $


The input

$ \,x(t)=cos(2t)\, $

can be rewritten as

$ \,x(t)=\frac{e^{2jt}+e^{-2jt}}{2}\, $

$ \,x(t)=\frac{1}{2}e^{2jt}+\frac{1}{2}e^{-2jt}\, $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood