Take P,The probability of not getting connected on any one day = (0.001)$ ^k $
(1-(.001$ ^k $))$ ^(365) $ Serves the condition "atlest"
Therefore 1-(1-(.001$ ^k $))$ ^(365) $ Tells us the proability of total outrage happening "atleast" once a year.
The above expression should be lesser or eual to 0.001....so solve the equation from thereon!!
