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* Send through system first then time shift | * Send through system first then time shift | ||
| − | x(t) <math>\to</math> (system) y(t) = 3+2*x(t) <math>\to</math> (time shift by T) z(t) = y(t-T) = 3+2*x(t-T) | + | ** x(t) <math>\to</math> (system) y(t) = 3+2*x(t) <math>\to</math> (time shift by T) z(t) = y(t-T) = 3+2*x(t-T) |
* Time shift first, then send through system | * Time shift first, then send through system | ||
Revision as of 18:36, 10 September 2008
Definition
A system is called 'time invariant' if for any input signal x(t) and for any time to that is a real number, the response to the shifted input x(t-T) is the shifted output y(t-T).
This is saying that for order for a signal to be considered 'time invariant' i must be able to put any signal through the system that has gone through a time shift, and i should get out another signal with the same time shift.
Another way to look at time invariance is that if I had a signal x(t) and i put i through a time delay of T, then through the system, I should get the same output if i put x(t) through the system first, and then shifted the output function of the system by T.
Example of Time Invariant System
Input signal x(t) and output which equals 3+2*x(t-T)
- Send through system first then time shift
- x(t) $ \to $ (system) y(t) = 3+2*x(t) $ \to $ (time shift by T) z(t) = y(t-T) = 3+2*x(t-T)
- Time shift first, then send through system
x(t) $ \to $ (time shift by T) y(t) = x(t-T) $ \to $ (system) w(t) = 3+2*y(t) = 3+2*x(t-T)
Since the two outputs are equal in this case, then it is safe to say that the system is time invariant.
Example of Time Variant System
input signal x(t) with a system of y(t) = x(2t) and time shift of T
