Line 4: | Line 4: | ||
==Part B== | ==Part B== | ||
The system does a phase shift to the right by 1 unit and then multiplies the amplitude of the function by the square of total shift. | The system does a phase shift to the right by 1 unit and then multiplies the amplitude of the function by the square of total shift. | ||
+ | |||
+ | if Y[n] = u[n-1] then k=0 because the function says that | ||
+ | |||
+ | <math>d[n-(k+1)]</math> |
Revision as of 12:59, 10 September 2008
Part A
Can the system be time invariant?
Part B
The system does a phase shift to the right by 1 unit and then multiplies the amplitude of the function by the square of total shift.
if Y[n] = u[n-1] then k=0 because the function says that
$ d[n-(k+1)] $