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https://www.projectrhea.org/rhea/dropbox_/381ea5db244c12bb92e6de3206725a7a/Wan82_CS5-4.PNG<br>
 
https://www.projectrhea.org/rhea/dropbox_/381ea5db244c12bb92e6de3206725a7a/Wan82_CS5-4.PNG<br>
 
<br>
 
<br>
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===Similar Problem===
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[https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_13/CS-5.pdf?dl=1 2013 QE CS5 Prob1]<br>
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[https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_09/CS-5%20QE%2009.pdf?dl=1 2009 QE CS5 Prob1]<br>
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[https://engineering.purdue.edu/ECE/Academics/Graduates/Archived_QE_August_08/CS-5%20QE%2008.pdf?dl=1 2008 QE CS5 Prob3]<br>
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[[QE_2017_CS-5|Back to QE CS question 5, August 2017]]
 
[[QE_2017_CS-5|Back to QE CS question 5, August 2017]]
  
 
[[ECE_PhD_Qualifying_Exams|Back to ECE Qualifying Exams (QE) page]]
 
[[ECE_PhD_Qualifying_Exams|Back to ECE Qualifying Exams (QE) page]]

Latest revision as of 11:00, 25 February 2019


ECE Ph.D. Qualifying Exam

Communication Signal (CS)

Question 5: Image Processing

August 2017 Problem 2


Solution

a)
$ sinc^2(\dfrac{t}{a}) \Rightarrow |a|\Lambda(af) $ (CTFT)
Wan82_CS5-2.PNG

b)
$ y(n)=sinc^2(\dfrac{nT}{a}) \Rightarrow X_s(f)=\dfrac{1}{T}\sum_{k=-\infty}^{\infty} X(f-kF)=\dfrac{|a|}{T}\sum_{k=-\infty}^{\infty}\Lambda(a(f-\dfrac{k}{T})) $

c)
minimum sampling frequency $ \dfrac{1}{T}\ge\dfrac{2}{a} $ $ f\ge\dfrac{2}{a} $ $ T\le\dfrac{a}{2} $

d)
$ T=\dfrac{a}{2} $
Wan82_CS5-3.PNG

e)
$ T=a $
Wan82_CS5-4.PNG


Similar Problem

2013 QE CS5 Prob1
2009 QE CS5 Prob1
2008 QE CS5 Prob3


Back to QE CS question 5, August 2017

Back to ECE Qualifying Exams (QE) page

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