Line 1: Line 1:
 
AC-2 2011
 
AC-2 2011
 +
 
P1.  
 
P1.  
 +
 
a) C=<math>\begin{pmatrix}
 
a) C=<math>\begin{pmatrix}
 
B & AB\end{pmatrix}=\begin{pmatrix}
 
B & AB\end{pmatrix}=\begin{pmatrix}

Revision as of 03:04, 16 May 2017

AC-2 2011

P1.

a) C=$ \begin{pmatrix} B & AB\end{pmatrix}=\begin{pmatrix} 1 & -1 \\ -3 & 3 \end{pmatrix} $

$ \Rightarrow $ Not controllable

Subspace $ \begin{pmatrix} 1 \\ -3 \end{pmatrix} $

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett