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| − | [[Category: | + | [[Category:ECE201]] |
| + | [[Category:ECE]] | ||
| + | [[Category:ECE201Spring2015Peleato]] | ||
| + | [[Category:circuits]] | ||
| + | [[Category:linear circuits]] | ||
| + | [[Category:problem solving]] | ||
| − | = | + | =Linear Network Practice= |
| + | <center><font size= 4> | ||
| + | '''Practice question for [[ECE201]]: "Linear circuit analysis I" ''' | ||
| + | </font size> | ||
| + | By: Chinar Dhamija | ||
| + | Topic: Linear Networks | ||
| − | + | </center> | |
| + | ---- | ||
| + | ==Question== | ||
| + | The box represents a linear network containing no independent sources. Given the data in the table below determine the voltage Vs' when Is = 4 A and Vout = 20V. | ||
| + | [[File:ECE201_P4_1.jpeg|300px|center]] | ||
| + | [[File:ECE201_P4_2.png|200px|center]] | ||
| + | ---- | ||
| + | ---- | ||
| + | ===Answer === | ||
| + | In order to find Vs' we have the following equation:<br /> | ||
| + | <math> 20 = Vs'a + 4b </math><br /> | ||
| − | [[ 2015 Spring ECE 201 Peleato|Back to 2015 Spring ECE 201 Peleato]] | + | From the information present in the table two systems of equations can be created to solve for a and b.<br /> |
| + | First equation:<br /> | ||
| + | <math> 10 = 4a + b </math><br /> | ||
| + | Second equation:<br /> | ||
| + | <math> 40 = 10a + 0b </math><br /> | ||
| + | After solving the above system of equations you get:<br /> | ||
| + | <math> a = 4 </math> and <math> b = -6 </math><br /> | ||
| + | |||
| + | Since we have both a and b values you can plug that into the Vs' equation and solve for Vs'.<br /> | ||
| + | <math>\begin{align} | ||
| + | 20 = Vs'a + 4b\\ | ||
| + | 20 = Vs'(4) + 4(-6)\\ | ||
| + | 44 = 4Vs'\\ | ||
| + | Vs' = 11 V | ||
| + | \end{align} | ||
| + | </math> | ||
| + | |||
| + | ---- | ||
| + | ==Questions and comments== | ||
| + | If you have any questions, comments, etc. please post them below | ||
| + | *Comment 1 | ||
| + | **Answer to Comment 1 | ||
| + | *Comment 2 | ||
| + | **Answer to Comment 2 | ||
| + | ---- | ||
| + | [[2015 Spring ECE 201 Peleato|Back to 2015 Spring ECE 201 Peleato]] | ||
| + | |||
| + | [[ECE201|Back to ECE201]] | ||
Revision as of 14:32, 2 May 2015
Linear Network Practice
Practice question for ECE201: "Linear circuit analysis I"
By: Chinar Dhamija
Topic: Linear Networks
Question
The box represents a linear network containing no independent sources. Given the data in the table below determine the voltage Vs' when Is = 4 A and Vout = 20V.
Answer
In order to find Vs' we have the following equation:
$ 20 = Vs'a + 4b $
From the information present in the table two systems of equations can be created to solve for a and b.
First equation:
$ 10 = 4a + b $
Second equation:
$ 40 = 10a + 0b $
After solving the above system of equations you get:
$ a = 4 $ and $ b = -6 $
Since we have both a and b values you can plug that into the Vs' equation and solve for Vs'.
$ \begin{align} 20 = Vs'a + 4b\\ 20 = Vs'(4) + 4(-6)\\ 44 = 4Vs'\\ Vs' = 11 V \end{align} $
Questions and comments
If you have any questions, comments, etc. please post them below
- Comment 1
- Answer to Comment 1
- Comment 2
- Answer to Comment 2
