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| − | *Review by | + | *Review by Michael Hayashi |
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| + | The examples you chose illustrated the Fourier transform well. A right arrow would help with the CTFT pair (in <math>\omega</math>) in the first example, and the example seems to flow the wrong direction: <br><math>X(f) = \mathcal{X}(\frac{\omega}{2\pi})</math><br>would more clearly establish that we want to obtain answers in terms of frequcny in Hertz. Ending the second example with a statement about the bidirectional nature of Fourier transform pairs would give even greater power to your examples. | ||
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Revision as of 21:25, 14 October 2014
Questions and Comments for
Fourier transform as a function of frequency $ \omega $ versus Fourier transform as a function of frequency fPlease post your reviews, comments, and questions below.
- Review by Michael Hayashi
The examples you chose illustrated the Fourier transform well. A right arrow would help with the CTFT pair (in $ \omega $) in the first example, and the example seems to flow the wrong direction:
$ X(f) = \mathcal{X}(\frac{\omega}{2\pi}) $
would more clearly establish that we want to obtain answers in terms of frequcny in Hertz. Ending the second example with a statement about the bidirectional nature of Fourier transform pairs would give even greater power to your examples.
- Review by Student 2
- Author answer here
- Review by Student 3
- Author answer here
- Review by Student 4
- Author answer here
- Review by Student 5
- Author answer here
