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<math>E=\int_0^{2\pi}{|sin(t)|^2dt}</math><br> | <math>E=\int_0^{2\pi}{|sin(t)|^2dt}</math><br> | ||
<math> =\int 0^(2\pi){\frac(1+sin(2t))/(2)dt)</math> | <math> =\int 0^(2\pi){\frac(1+sin(2t))/(2)dt)</math> | ||
| + | <math>=\frac{\int_0^{2\pi}(1+cos(2t))dt}{2}</math> | ||
Revision as of 18:25, 2 September 2008
x(t) = sin t
Energy
$ E=\int_0^{2\pi}{|sin(t)|^2dt} $
$ =\int 0^(2\pi){\frac(1+sin(2t))/(2)dt) $
$ =\frac{\int_0^{2\pi}(1+cos(2t))dt}{2} $
