(New page: == Finding the Inverse of Complex Numbers ==) |
(→Finding the Inverse of Complex Numbers) |
||
Line 1: | Line 1: | ||
== Finding the Inverse of Complex Numbers == | == Finding the Inverse of Complex Numbers == | ||
+ | |||
+ | <math>1/(a + bi) = {a\over a^2+b^2}+ \left( {-b\over a^2+b^2}\right)i</math> |
Revision as of 04:23, 2 September 2008
Finding the Inverse of Complex Numbers
$ 1/(a + bi) = {a\over a^2+b^2}+ \left( {-b\over a^2+b^2}\right)i $