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*If |G| = p<sup><span class="texhtml">α</span></sup>m where p does not divide m, then a subgroup of order p<sup><span class="texhtml">α</span></sup> is called a Sylow p-subgroup of G. | *If |G| = p<sup><span class="texhtml">α</span></sup>m where p does not divide m, then a subgroup of order p<sup><span class="texhtml">α</span></sup> is called a Sylow p-subgroup of G. | ||
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==Regular p-groups== | ==Regular p-groups== | ||
'''Definitons:''' | '''Definitons:''' |
Revision as of 09:43, 30 November 2013
Mark Rosinski, markrosi@purdue.edu Joseph Lam, lam5@purdue.edu Beichen Xiao, xiaob@purdue.edu
Outline:
Origin -Creator -History of the Sylow Theorems/ p-groups P-Groups -Definition -Regular p-groups
-Relationship to Abelian Groups
-Application -Frattini Subgroup
-Special p groups -Pro p-groups -Powerful p-groups
Sylow Theorems -Application
-Theorem 1
-Theorem 2 -Theorem 3
-Importance of Lagrange Theory
Contents
I plan on deleting everything above this after we have completed the paper. I planned on just using the outline as a guide.
I've been using these websites:
http://math.berkeley.edu/~sikimeti/SylowNotes.pdf
http://omega.albany.edu:8008/Symbols.html (this is Tex symbols)
http://www.ams.org/journals/bull/2001-38-03/S0273-0979-01-00909-0/S0273-0979-01-00909-0.pdf
and also the pdf emailed to you
http://groupprops.subwiki.org/wiki/Regular_p-group regular p-group
http://people.maths.ox.ac.uk/craven/docs/lectures/pgroups.pdf this one is almost about everything.
P-groups
Definitions:
- Let p be a prime p $ \in $ $ \mathbb{Z} $ such that $ \mathbb{Z} $≥0. A p-group is a group of order pn.
- A subgroup of order pk for some k ≥ 1 is called a p-subgroup.
- If |G| = pαm where p does not divide m, then a subgroup of order pα is called a Sylow p-subgroup of G.
\usepackage{relsize}
Regular p-groups
Definitons:
- For every \mathlarger{a, b} $ \in $$ \mathlarger{G} $, there exists $ \mathlarger{c} $$ /in $$ \mathlarger{{[<a,b>,<a,b>]} $
Sylow's Theorems
Definitions:
Let G be a group of order pαm, where p is a prime, m≥1, and p does not divide m. Then:
- Sylp(G) $ \neq $Failed to parse (lexing error): \0
All Sylow p-subgroups are conjugate in G. To expand, if P1 and P2 are both Sylow p-subgroups, then there is some g