Line 14: Line 14:
  
 
Therefore 6 must be the unity.
 
Therefore 6 must be the unity.
 +
 +
*HI There! By the way, you can use the latex command \neq to made the symbol "not equal to". In fact, using latex, your post could look like this
 +
:<math>
 +
\begin{align}
 +
2\times 2 &= 4 \\
 +
\text{ but } 4\text{ mod } 10 &= 4 \neq 2.
 +
\end{align}
 +
</math>
 +
:Thus 2 cannot be a unity.
 +
:<math>
 +
\begin{align}
 +
4\times 4 &=16 \\
 +
\text{but } 16 mod 10 &= 6 \neq 4.
 +
\end{align}
 +
</math>
 +
:Thus 4 cannot be a unity.
 +
:<math>
 +
\begin{align}
 +
6\times 6 &= 36 \\
 +
\text{and } 36\text{ mod }10 &= 6. \text{ (Check) }
 +
\end{align}
 +
</math>
 +
:But this is not enough. We must check what effect multiplying 6 has on the other elements.
 +
:<math>
 +
\begin{align}
 +
0\times 6 &= 0 \text{ and } 0 \text{ mod } 10 = 0. \text{ (Check) } \\
 +
2\times 6 &= 12 \text{ and } 12 \text{ mod } 10 = 2. \text{ (Check) }\\
 +
4\times 6 &= 24 \text{ and } 24 \text{ mod } 10 = 4. \text{ (Check) }\\
 +
8\times 6 &= 48 \text{ and } 48 \text{ mod } 10 = 8. \text{ (Check) }\\
 +
\end{align}
 +
</math>
 +
  
 
--[[User:Bakey|Bakey]] 08:45, 10 October 2012 (UTC)
 
--[[User:Bakey|Bakey]] 08:45, 10 October 2012 (UTC)

Latest revision as of 07:29, 19 October 2012

The problem is giving you that the {0, 2 , 4 , 6 ,8} under addition and multiplication modulo 10 has a unity, and wants you to find it.

  By definition we know the unity of a ring is a nonzero element that is an identity under multiplication. 
  Furthermore, if we consider each element of {0, 2 ,4 , 6, 8} (other than zero) we can see which element has this property.
  Note: Let the symbol '<>' be equivalent to "not equal to"

2*2= 4 but 4 mod 10 = 4 <> 2. Thus 2 cannot be a unity. 4*4 =16 but 16 mod 10 = 6 <> 4. Thus 4 cannot be a unity. 6*6 = 36 and 36 mod 10 = 6. (Check) But this is not enough. We must check what effect multiplying 6 has on the other elements. 0*6 = 0 and 0 mod 10 = 0. (Check) 2*6 = 12 and 12 mod 10 = 2. (Check) 4*6 = 24 and 24 mod 10 = 4. (Check) 8*6 = 48 and 48 mod 10 = 8. (Check)

Therefore 6 must be the unity.

  • HI There! By the way, you can use the latex command \neq to made the symbol "not equal to". In fact, using latex, your post could look like this
$ \begin{align} 2\times 2 &= 4 \\ \text{ but } 4\text{ mod } 10 &= 4 \neq 2. \end{align} $
Thus 2 cannot be a unity.
$ \begin{align} 4\times 4 &=16 \\ \text{but } 16 mod 10 &= 6 \neq 4. \end{align} $
Thus 4 cannot be a unity.
$ \begin{align} 6\times 6 &= 36 \\ \text{and } 36\text{ mod }10 &= 6. \text{ (Check) } \end{align} $
But this is not enough. We must check what effect multiplying 6 has on the other elements.
$ \begin{align} 0\times 6 &= 0 \text{ and } 0 \text{ mod } 10 = 0. \text{ (Check) } \\ 2\times 6 &= 12 \text{ and } 12 \text{ mod } 10 = 2. \text{ (Check) }\\ 4\times 6 &= 24 \text{ and } 24 \text{ mod } 10 = 4. \text{ (Check) }\\ 8\times 6 &= 48 \text{ and } 48 \text{ mod } 10 = 8. \text{ (Check) }\\ \end{align} $


--Bakey 08:45, 10 October 2012 (UTC)

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