(New page: I did the first one by contradiction and a lot of cases. <math>Test, $\sup$ \sup</math>)
 
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I did the first one by contradiction and a lot of cases.
 
I did the first one by contradiction and a lot of cases.
  
<math>Test, $\sup$ \sup</math>
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<math>Given A, B \neq \varnothing \subseteq \mathbf{R}, A+B = \{ a+b \vert a \in A, b \ in B \}
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WTS:  \sup(A+B) = \supA + \sup B</math>

Revision as of 04:33, 28 August 2008

I did the first one by contradiction and a lot of cases.

$ Given A, B \neq \varnothing \subseteq \mathbf{R}, A+B = \{ a+b \vert a \in A, b \ in B \} \newline WTS: \sup(A+B) = \supA + \sup B $

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