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===Answer 3===
 
===Answer 3===
 
The answer is zero since impulse function is 0 everywhere except n = 0.
 
The answer is zero since impulse function is 0 everywhere except n = 0.
 +
:Instructor's comments: Ok, I guess I am going to have to be a bit more specific. I would like to see a way to answer this question as a sequence of small changes to this expression until you get to zero. Something like
 +
:<math>
 +
\begin{align}
 +
\sum_{n=-\infty}^\infty n \delta [n] &= \text{ blah } \\
 +
&= \text{ blih} \\
 +
&= 0
 +
\end{align}
 +
</math>
 +
:Can you try that? -pm
 
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[[2011_Fall_ECE_438_Boutin|Back to ECE438 Fall 2011 Prof. Boutin]]
 
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Revision as of 08:42, 26 August 2011

Simplify this summation

$ \sum_{n=-\infty}^\infty n \delta [n]  $

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You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too!


Answer 1

The answer is 0 ?

Instructor's comment: Yes, it's zero. Can you justify your answer? -pm

Answer 2

The delta function is zero everywhere except when n=0 and since we are multiplying the delta by n the answer would thus be 0.

Instructor's comment: Yes, that's the idea. Now can you justify your answer "in math" instead of "in words"? -pm

Answer 3

The answer is zero since impulse function is 0 everywhere except n = 0.

Instructor's comments: Ok, I guess I am going to have to be a bit more specific. I would like to see a way to answer this question as a sequence of small changes to this expression until you get to zero. Something like
$ \begin{align} \sum_{n=-\infty}^\infty n \delta [n] &= \text{ blah } \\ &= \text{ blih} \\ &= 0 \end{align} $
Can you try that? -pm

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