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What is the Nyquist rate of the signal | What is the Nyquist rate of the signal | ||
− | + | '''Failed to parse (lexing error): x(t) = \frac{ \sin ( \pi t )}{\pi t} \frac{ \sin ( \pi t )}{\pi t} ?''' | |
+ | |||
+ | ^ Sorry, I think I broke the equation in the problem statement but I don't know how to fix it. -ke<br> | ||
---- | ---- | ||
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=== Answer 1 === | === Answer 1 === | ||
− | Use CTFT to find the frequency response | + | Use CTFT to find the frequency response |
− | + | ||
− | + | ||
− | + | ||
− | + | ||
− | + | Using table, we know FT(sin(pi t)/(pi t)) --> u(w+W) - u(w-W) | |
− | + | X(w) = [u(w+pi) - u(w-pi)] * [u(w+pi) - u(w-pi)] | |
− | | + | = int<sub>-infinity</sub><sup>infinity</sup> ( [u(W+pi) - u(W-pi)] [u(w-W+pi) - u(w-W-pi)] )dW<sup></sup><sub></sub><sub></sub> |
− | | + | = int-<sub>pi</sub><sup>pi</sup> (u(w-W+pi) - u(w-W-pi)) dW |
− | + | since W-pi <= w < pi-W, and -pi <= W < pi | |
− | | + | -2pi <= w < 2pi |
− | + | I'm not sure if I did the convolution right... help please (if you can read it) | |
− | | + | int<sub>pi</sub><sup>-w-pi</sup>dW if -2pi <= w < 0 |
+ | X(w) = { int<sub>w-pi</sub><sup>pi</sup>dW if 0 <= w < 2pi | ||
+ | 0 else | ||
− | + | <br> | |
− | | + | -w-2pi if -2pi <= w < 0 |
− | | + | = { 2pi-w if 0 <= w < 2pi |
+ | 0 else | ||
+ | <br> | ||
− | Regardless, wm = 2pi so NR = 4pi | + | Regardless, wm = 2pi so NR = 4pi |
− | --[[User:Kellsper|Kellsper]] 22:36, 20 April 2011 (UTC)<br> | + | --[[User:Kellsper|Kellsper]] 22:36, 20 April 2011 (UTC)<br> |
=== Answer 2 === | === Answer 2 === |
Revision as of 17:40, 20 April 2011
Contents
Practice Question on Nyquist rate
What is the Nyquist rate of the signal
Failed to parse (lexing error): x(t) = \frac{ \sin ( \pi t )}{\pi t} \frac{ \sin ( \pi t )}{\pi t} ?
^ Sorry, I think I broke the equation in the problem statement but I don't know how to fix it. -ke
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Answer 1
Use CTFT to find the frequency response
Using table, we know FT(sin(pi t)/(pi t)) --> u(w+W) - u(w-W)
X(w) = [u(w+pi) - u(w-pi)] * [u(w+pi) - u(w-pi)]
= int-infinityinfinity ( [u(W+pi) - u(W-pi)] [u(w-W+pi) - u(w-W-pi)] )dW
= int-pipi (u(w-W+pi) - u(w-W-pi)) dW
since W-pi <= w < pi-W, and -pi <= W < pi
-2pi <= w < 2pi
I'm not sure if I did the convolution right... help please (if you can read it)
intpi-w-pidW if -2pi <= w < 0
X(w) = { intw-pipidW if 0 <= w < 2pi
0 else
-w-2pi if -2pi <= w < 0
= { 2pi-w if 0 <= w < 2pi
0 else
Regardless, wm = 2pi so NR = 4pi
--Kellsper 22:36, 20 April 2011 (UTC)
Answer 2
Write it here
Answer 3
Write it here.