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w<sub>s</sub> > 6pi | w<sub>s</sub> > 6pi | ||
− | T = 2pi/w<sub>s</sub> < 2/6 = 1/3 | + | T = 2pi/w<sub>s</sub> < 2/6 = 1/3 |
+ | <br> | ||
+ | The signal can be reconstructed for all T < 1/3. | ||
+ | --[[User:Ssanthak|Ssanthak]] 12:09, 20 April 2011 (UTC) | ||
− | |||
=== Answer 2 === | === Answer 2 === |
Revision as of 07:09, 20 April 2011
Contents
The signal
$ x(t)= \frac{\sin (3 \pi t)}{\pi t} $
is sampled with a sampling period T. For what values of T is it possible to reconstruct the signal from its sampling?
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Answer 1
from the Table
x(w) = u(w+3pi)-u(w-3pi)
Thus the signal is bandlimited with a wm = 3pi
We must sample above the Nyquist Rate which is equal to 2wm or 6pi
ws > 6pi
T = 2pi/ws < 2/6 = 1/3
The signal can be reconstructed for all T < 1/3. --Ssanthak 12:09, 20 April 2011 (UTC)
Answer 2
Write it here
Answer 3
Write it here.