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For question 1, is omega_c > 0 the same as "there are no conditions set"?
 
For question 1, is omega_c > 0 the same as "there are no conditions set"?
 
:no, because it excludes <math>\omega_c=0</math>. The carrier frequency <math>\omega_c=0</math> could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm
 
:no, because it excludes <math>\omega_c=0</math>. The carrier frequency <math>\omega_c=0</math> could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm
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For question 1b), should <math class="inline">e^{-j(\omega_c+\theta_c)}</math> be <math class="inline">e^{-j(\omega_ct+\theta_c)}</math> ?

Revision as of 06:41, 19 April 2011

For question 1, is omega_c > 0 the same as "there are no conditions set"?

no, because it excludes $ \omega_c=0 $. The carrier frequency $ \omega_c=0 $ could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm

For question 1b), should $ e^{-j(\omega_c+\theta_c)} $ be $ e^{-j(\omega_ct+\theta_c)} $ ?

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang