(New page: For question 1, is omega_c > 0 the same as "there are no conditions set"?)
 
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For question 1, is omega_c > 0 the same as "there are no conditions set"?
 
For question 1, is omega_c > 0 the same as "there are no conditions set"?
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:no, because it excludes <math>\omega_c=0</math>. The carrier frequency <math>\omega_c=0</math> could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm

Revision as of 11:44, 18 April 2011

For question 1, is omega_c > 0 the same as "there are no conditions set"?

no, because it excludes $ \omega_c=0 $. The carrier frequency $ \omega_c=0 $ could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm

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Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin