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| + | =How to Evaluate a Complicated Sum= | ||
| + | Does somebody know how to calculate the sum | ||
| − | = | + | <math> \sum_{k=-\infty}^\infty \frac{1}{1+k^2} ? \ </math> |
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| + | Wolfram said answer is '''π * coth(π)'''. is there any easier way to do that? Yimin. Jan 20 | ||
| + | ---- | ||
| + | ==Discussion/help== | ||
| + | *Write here. | ||
| + | **Answer here | ||
| + | *Write here | ||
| + | ---- | ||
[[ Discussion HW2 ECE301 Spring2011|Back to Discussion HW2 ECE301 Spring2011]] | [[ Discussion HW2 ECE301 Spring2011|Back to Discussion HW2 ECE301 Spring2011]] | ||
Revision as of 03:46, 21 January 2011
How to Evaluate a Complicated Sum
Does somebody know how to calculate the sum
$ \sum_{k=-\infty}^\infty \frac{1}{1+k^2} ? \ $
Wolfram said answer is π * coth(π). is there any easier way to do that? Yimin. Jan 20
Discussion/help
- Write here.
- Answer here
- Write here
