(New page: ---- In question 2e <math> x(t)= \sum_{k=-\infty}^\infty \frac{1}{1+(x-7k)^2} \ </math> <br> should it be<math> x(t)= \sum_{k=-\infty}^\infty \frac{1}{1+(t-7k)^2} \ </math> ? ...)
 
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and I was trying to find out what the peak value is for this question but turns out to be very hard to calculate something like this<math> \sum_{t=-\infty}^\infty \frac{1}{1+t^2} \ </math> and wolfram said answer is  π * coth(/pi). is there any easier way to do that?
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and I was trying to find out what the peak value is for this question but turns out to be very hard to calculate something like this<math> \sum_{t=-\infty}^\infty \frac{1}{1+t^2} \ </math> and wolfram said answer is  π * coth(π). is there any easier way to do that?
  
 
Yimin.
 
Yimin.
 
Jan 20
 
Jan 20
 
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Revision as of 04:35, 20 January 2011


In question 2e $ x(t)= \sum_{k=-\infty}^\infty \frac{1}{1+(x-7k)^2} \ $


should it be$ x(t)= \sum_{k=-\infty}^\infty \frac{1}{1+(t-7k)^2} \ $ ?


and I was trying to find out what the peak value is for this question but turns out to be very hard to calculate something like this$ \sum_{t=-\infty}^\infty \frac{1}{1+t^2} \ $ and wolfram said answer is π * coth(π). is there any easier way to do that?

Yimin. Jan 20


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Questions/answers with a recent ECE grad

Ryne Rayburn